Why Does 5^2 Equal 7 in Go?

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Why Does 5^2 Equal 7 in Go?

in go, `5^2` equals 7 because the `^` symbol does **not** mean “to the power of”; instead, it’s the **bitwise xor operator**, which performs exclusive or on corresponding bits of two Integers.

To understand why 5 ^ 2 == 7, let’s break it down step by step:

  • Decimal 5 in binary is 101
  • Decimal 2 in binary is 010
  • Aligning bits and applying XOR (1 if bits differ, 0 if same):
101  (5) ^  010  (2) -------    111  (7)

So 101 XOR 010 = 111₂ = 7₁₀.

⚠️ Important notes:

  • go has no built-in exponentiation operator. To compute powers like 5², use math.Pow(5, 2) (which returns float64) or implement integer exponentiation manually.
  • The ^ operator is also used for bitwise complement when unary (e.g., ^x flips all bits of x), but as a binary operator, it’s always XOR.
  • Confusion often arises from languages like python (**) or matlab (^) where ^ does mean exponentiation—but not in Go.

✅ Correct ways to compute 5² in Go:

import "math"  // For float64 result result := math.Pow(5, 2) // 25.0  // For integer exponentiation (safe for small, non-negative exponents) func powint(base, exp int) int {     result := 1     for i := 0; i < exp; i++ {         result *= base     }     return result } fmt.Println(powInt(5, 2)) // 25

Always double-check operator semantics—especially with symbols like ^, &, and |—as their meanings are bitwise in Go, not arithmetic or logical in the conventional sense.

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